<PRE><B>Question 541455</B>
B=4A-21
C=5A+1
A=A&lt;P&gt;
The above is given.  The interior angles of a triangle add to 180.&lt;P&gt;
4A-21 + 5A+1 + A =180&lt;P&gt;
10A-20=180&lt;P&gt;
10A = 200&lt;P&gt;
A = 20&lt;P&gt;
B=4A-21=4(20)-21=59&lt;P&gt;
C=5A+1=5(20)+1=101&lt;P&gt;
When you know the measure of all interior angles, you can find the two exterior angels adjacent to each interior angle by subtracting the interior angle from 180.&lt;P&gt;
The two exterior angles adjacent to A = 180-20=160&lt;P&gt;
The two exterior angles adjacent to B = 180=59=121&lt;P&gt;
The two exterior angles adjacent to C = 180-101=79
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