Question 541212
 f(x)=(x+4)/(X^2+x-6) 
find out the 
graph 
{{{graph(400,400,-10,10,-10,10,(x+4)/(x^2+x-6))}}}
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vertical asymptotes
Solve x^2+x-6 = 0
(x+3)(x-2) = 0
x = -3 ; x = 2
Those are the vertical asymptotes
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horizontal asymptote
y = 0x^2/1x^2 = 0/1 = 0
That is the horizontal asymptote
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Domain:
All Real Numbers except x = 2 and x = -3
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Cheers,
Stan H.
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