Question 541136
percent		----------------			quantity								
Alcohol I	20	----------------			x	gallons							
Alcohol II	50	------	9	-	x	gallons							
Mixture	30.00%	----------------	9										
													
20x+50(	9-x)=30*9	
													
20x+450	-50x=	270			
20x-50x	=270-450			
-30x=-180								
/-30												
x	=	6	gallons			20.00%		Alcohol I	
	3		gallons			50.00%		Alcohol II	
													
m.ananth@hotmail.ca