Question 53097
Let the 1st integer=x
The the 2nd integer=x+1
Therefore your problem to solve is:
8x+6(x+1)=48
8x+6x+6=48
14x+6=48
14x+6-6=48-6
14x=42
14x/14=42/14
x=3
The 1st integer=x=3
The sencond integer=x+1=3+1=4