Question 541034
{{{1-(a+b)^3}}}



{{{1^3-(a+b)^3}}}



{{{(1-(a+b))(1^2+1*(a+b)+(a+b)^2)}}} Note: use the difference of cubes factoring formula here



{{{(1-(a+b))(1+a+b+(a+b)^2)}}} 



{{{(1-a-b)(1+a+b+a^2+2ab+b^2)}}}



So {{{1-(a+b)^3=(1-a-b)(1+a+b+a^2+2ab+b^2)}}}



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