Question 539802
Hi I am trying to figure out how to find the equation of a circle if the center is (4,4) and it passes through (-5,0)
**
Standard form of equation of circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
..
Using given coordinates of center (4,4) and point (-5,0)
(-5-4)^2+(0-4)^2=r^2
(-9)^2+(-4)^2=r^2
81+16=r^2
97=r^2
r=√97
equation of circle:  (x-4)^2+(y-4)^2=97