Question 539049
Use this formula:
{{{p*((1+i)^n)=x}}}
p=original principal
i=interest rate per compounding period
n=number of compounding periods
x=new amount of money
So start pulling pieces from the question. 
-What was the original amount you started with? $450 (p)
-What is the interest rate per compounding period? 10% (i) 
-How many times does it compound? 2 (n)
-We are looking for X
So take the original formula
{{{p*((1+i)^n)=x}}}
substitute in what you know, and solve for X
{{{450*((1+.10)^2)=x}}}
{{{x=450*(1.1^2)=450*1.21=544.50}}}
So you started with $450 and ended with $544.50. How much does that mean you earned?
{{{544.50-450=94.50}}}