Question 540774
Given the points A(3, -6) and B(9, 2). Find the equation of the perpendicular bisector through the line segment AB. 
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Find slope and midpoint of AB:
slope = (2--6)/(9-3) = 8/6 = 4/3
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midpoint = (x,y)
x = (3+9)/2 = 6
y = (-6+2)/2 = -2
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Now find the eqution of the line 
with slope = -3/4 passing thru point (6,-2)
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Form: y = mx + b
-2 = (-3/4)*6 + b
-2 = -9/2 + b
b = -2 + (9/2)
b = 5/2
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Equation you want:
y = (-3/4)x + (5/2)
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Cheers,
Stan H.
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