Question 540743
{{{1/(x+3) = ((7x+4)/(x^2+4x+3)) - 1/(x+1)}}}


Factorise x^2+4x+3

=x^2+3x+x+3
=x(x+3)+1(x+3)

=(x+1)(x+3)

{{{1/(x+3) = ((7x+4)/((x+3)(x+1))) - 1/(x+1)}}}

LCD of the equation = (x+1)(x+3)

multiply equation by (x+1)(x+3)

{{{((x+1)(x+3))/(x+3) = (((7x+4)(x+1)(x+3))/((x+3)(x+1))) - ((1*(x+1)(x+3))/(x+1)(x+3))}}}
Cancel off the common terms
x+1=7x+4-x-3

5x=0
x=0

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