Question 540669
x1		y1	x2	y2				
-4		-8	-8	3				
								
slope m =		(y2-y1)/(x2-x1)						
(	3	-	-8	)/(	-8	-	-4	) 
(	11	/	-4	)  				
m=		-11/ 4						 
								
Plug value of  the slope  and point (	-4,-8	) in	
Y 	=	m	x 	+	b			
-8.00	=	11    	+	b				
b=	-8	-	-11    					
b=	3      							
So the equation  will be								
Y 	=	-11/4	x 	+	3 
multiply by 4
4y=-11x+12
Now you can write in any form you wish   			
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