Question 540614
{{{-12x^2-28x+24 = -4(3x^2+7x-6)=-4(3x - 2 )(x + 3 )}}}<P>
{{{q^2 + 1}}} can be recognized as the difference of two squares for complex terms.<P>
{{{q^2 + 1 = (q+1i)(q-1i)}}}<P>
If you need proof of that, use FOIL to multiply those complex numbers. 
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