Question 540508
2m+3=2z


2*(2m+3)=2*2z



4m+6=4z



4m=4z-6


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4m+9z=7



(4z-6)+9z=7



13z-6=7



13z=13



z=1


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4m=4z-6



4m=4(1)-6



4m=-2



m = -2/4



m = -1/2



So the solutions are m = -1/2 and z = 1



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