Question 540486
let base be x
height = x-7

hypotenuse = 13

By Pythagoras theorem
leg1^2+leg2^2=13^2

x^2+(x-7)^2=169
x^2+x^2-14x+49=169
2x^2-14x-120=0

/2
x^2-7x-60=0
x^2-12x+5x-60=0
x(x-12)+5(x-12)=0
(x-12)(x+5)=0
Take the positive root

One leg =12 
Other = 12-7=5
The sides are 5,12 & 13

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