Question 540470
Let {{{ w }}} = liters of water to be added
given:
{{{ .5*10 = 5 }}} liters of acid in 50% solution
{{{ 5 / ( 10 + w ) = .2 }}}
{{{ 5 = .2*( 10 + w ) }}}
{{{ 5 = 2 + .2w }}}
{{{ .2w = 3 }}}
{{{ w = 3/.2 }}}
{{{ w = 15 }}}
15 liters of water must be added