Question 540391
isoscles right triangle

let one leg be x
other leg is also x

By Pythagoras theorem
{{{x^2+x^2=2^2}}}

2x^2=4
x^2=2

{{{x= sqrt(2)}}} The positive root

Area of right triangle = 1/2 * leg1 * leg2
{{{Area = (1/2) * sqrt(2)*sqrt(2)}}}
Area = 1 sq. unit