<PRE><B>Question 539528</B>
how many pounds of seed worth $1.05 per pound must be mixed with 60 pounds of seed worth $.90 per pound in order to produce a mixture to sell for $1.00 per pound? (I added the decimal to $90)
:
Let x = amt of 1.05 seed required
then
(x+60) = the resulting mixture
:
Write typical mixture equation:
:
1.05x + .90(60) = 1(x+60)
1.05x + 54 = x + 60
1.05x - x = 60 - 54
.05x = 6
x = {{{6/.05}}}
x = 120 lb of 1.05 seed required
:
:
Check the solution in the original equation
1.05(120) + .9(60) = 1(120+60)
126 + 54 = 180
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