Question 539566
log2(2x) + log2(x+3) = 3
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log2[2x(x+3)] = 3
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2x(x+3) = 2^3
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2x^2+6x-8 = 0
x^2+3x-4 = 0
Factor:
(x+4)(x-1) = 0
Positive solution:
x = 1
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Cheers,
Stan H.