<PRE><B>Question 539272</B>
In a race, if a dog going 37 mph gets a headstart of 12 yards, how long will it take a dog going 38 mph to catch up?
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The difference in speed is 1 mi/hr = 22/15 ft/sec
12 yds = 36 ft
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d = r*t
t = d/r = 36/(22/15) = 270/11 seconds
~ 24.5 seconds
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Note that the time would be the same if the speeds are both &gt;0 and differ by 1 mi/hr.</PRE>