Question 539040
rearranging the equation, we have,
-3x^2-4x+6=0
find:
a=-3
b=-4
c=6

using the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
substitute the values. We have,
{{{x = (-(-4) +- sqrt( (-4)^2-4*(-3)*(6) ))/(2*(-3)) }}}
={{{(4 +- sqrt( 16+72 ))/(-6) }}}
={{{(4 +- sqrt( 98 ))/(-6) }}}
={{{(4 +- sqrt( 49*2 ))/(-6) }}}
={{{(4 +- 7sqrt( 2 ))/(-6) }}}

for x1: = {{{(4 + 7sqrt( 2 ))/(-6) }}}
        = -2.31...

for x2: = {{{(4 - 7sqrt( 2 ))/(-6) }}}
        = 0.98...