Question 538917
You could start with Ohm's law:
{{{E = I*R}}} Solve for I.
{{{I = E/R}}} Substitute I = 0.5 amps. and R = 240 ohms.
{{{0.5 = E/240}}} Solve for E.
{{{E = 0.5(240)}}}
{{{E = 120}}} Now Ohm's law looks like:
{{{I = 120/R}}} Substitute R = 960 ohms.
{{{I = 120/960}}} Evaluate.
{{{I = 0.125}}} amperes.