Question 538928


{{{(2x-5)^2=81}}} Start with the given equation.



{{{2x-5=""+-sqrt(81)}}} Take the square root of both sides.



{{{2x-5=sqrt(81)}}} or {{{2x-5=-sqrt(81)}}} Break up the "plus/minus" to form two equations.



{{{2x-5=9}}} or {{{2x-5=-9}}}  Take the square root of {{{81}}} to get {{{9}}}.



{{{2x=5+9}}} or {{{2x=5-9}}} Add {{{5}}} to both sides.



{{{2x=14}}} or {{{2x=-4}}} Combine like terms.



{{{x=7}}} or {{{x=-2}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



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Answer:



So the solutions are {{{x=7}}} or {{{x=-2}}}.



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