Question 538688
{{{(p^(-3)+q^(-2))/q^(-1)}}}
<pre>
Make two fractions:

{{{p^(-3)/q^(-1)}}} + {{{q^(-2)/q^(-1)}}}

Get all the negative exponents positive by

using this rule: {{{X^(-N)/Y^(-M)}}} = {{{Y^M/X^N}}}

[That is, an exponential with a negative exponent 
which is a numerator (denominator) or a factor 
thereof may be brought from the numerator(denominator) 
to the denominator (numerator), and the sign of the
exponent changed to positive.]

{{{q^1/p^3}}} + {{{q^1/q^2}}}
  
In the second fraction, we can divide top and bottom by q:

{{{q^1/p^3}}} + {{{1/q^1}}}

We can erase the 1 exponents

{{{q/p^3}}} + {{{1/q}}}

That is one form of the answer.  Or you can combine the
fractions over the LCD of p³q

{{{(q^2+p^3)/(p^3q)}}}

Edwin</pre>