Question 538443
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You didn't bother to share the exact relationships, so we'll just have to assign those relationships to variables and see what develops.


Let *[tex \Large x] represent the first number, *[tex \Large y] represent the second number, and *[tex \Large z] represent the third number.  Further, let *[tex \Large S] represent the sum of the three numbers, let *[tex \Large d] represent the amount by which the first number is greater than the second, and the *[tex \Large m] represent the factor by which the third number exceeds the second.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ +\ z\ =\ S]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ y\ +\ d]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z\ =\ my]


Substituting from equation 2 and 3 into 1:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ +\ d\ +\ y\ +\ my\ =\ S]


A little Algebra music...


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (m\ +\ 2)y\ =\ S\ -\ d]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{S\ -\ d}{m\ +\ 2}]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{S\ -\ d}{m\ +\ 2}\ +\ d]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z\ =\ m\left(\frac{S\ -\ d}{m\ +\ 2}\right)]





John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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