Question 538211
{{{ P = P[0]*e^(r*t) }}}
given:
{{{ P[0] = 5000 }}}
{{{ r = .005 }}}
The year 2000 would be {{{ t = 10 }}}
The year 2006 would be {{{ t = 16 }}}
{{{ P = 5000*e^(.005*16) }}}
{{{ P = 5000*e^.08 }}}
You can use calculator to find this.
I can't locate mine