Question 537924
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The perimeter of a rectangle with dimensions *[tex \Large l] and *[tex \Large w] is given by *[tex \Large P_1\ =\ 2l\ +\ 2w]


Then the perimeter of a rectangle with dimensions *[tex \Large kl] and *[tex \Large kw] is given by *[tex \Large P_2\ =\ 2(kl)\ +\ 2(kw)]


Factor out *[tex \Large k]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_2\ =\ k(2l\ +\ 2w)\ =\ kP_1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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