Question 537309
Assuming *[tex \LARGE 4^{\frac{1}{2}} + 2] (as opposed to *[tex \LARGE 4^{\frac{1}{2} + 2}]), this number is equal to 2+2, or 4. This is a real and rational number. Technically, it is also considered a complex number because it can be graphed on the complex plane (or written as 4+0i).