Question 537454
Let H = # $ invested at 10%
Let L = # $ invested at 6%
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Given:
H + L = 15,000
.10H + .06L = 1,260
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With a system of two equations with two unknowns, rewrite one of the equations so that it is written for one unknown in terms of the other unknown.
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H + L = 15,000
H = 15,000 - L
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substitute H = 15,000 - L into the 2nd equation:
.10(15,000 - L) + .06L = 1,260
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simplify by combining like terms:
1,500 - .10L + .06L = 1,260
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subtract 1,500 from both sides:
-.04L = -240
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divide both sides by -.04:
L = $6,000
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This represents the amount of money invested at 6%.  To find the amount of money invested at 10%, go back to our H = 15,000 - L equality and solve for H:
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H = 15,000 - 6,000
H = $9,000
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H = $9,000 equals the amount of money invested at 10%.
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Check your work by inserting H = 9,000 and L = 6,000 into the 2nd equation:
.10(9,000) + .06(6,000) = 1,260
900 + 360 = 1,260
1,260 = 1,260 checks...
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Cheers,
Lee