Question 537430
how do i solve and graph this parabola x2+y2+6x-8y=11?
It is not a parabola; it is a circle:
Complete the square on the x and on the y terms:
(x^2+6x+9) + (y^2-8y+16) = -11+9+16
(x+3)^2+ (y-4)^2= 14
Center at (-3,4); radius = sqrt(14)
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how do i solve this y^2/4-x^2/25=1
Hyperbola with center at (0,0) ; opening up and down;
y-intercept at (0,2) and (0,-2)
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how do i solve this equation 4x^2+y^2=16
Ellipse:
x^2/(1/4) + y^2/16 = 1
Center at (0,0); semi-major axis = 4 ; semi-minor axis = 1/2
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Cheers,
Stan H.
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