Question 537345


*[Tex \LARGE y+1=\frac{1}{3}(x-4)]


*[Tex \LARGE y+1=\frac{1}{3}x-\frac{1}{3}*4]


*[Tex \LARGE y+1=\frac{1}{3}x-\frac{4}{3}]


*[Tex \LARGE y=\frac{1}{3}x-\frac{4}{3}-1]


*[Tex \LARGE y=\frac{1}{3}x-\frac{4}{3}-\frac{3}{3}]


*[Tex \LARGE y=\frac{1}{3}x-\frac{7}{3}]


The equation is now in y = mx+b form where {{{m = 1/3}}} and {{{b = -7/3}}}


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