Question 537262
Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 10 more than three times the largest number.
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1st: x-1
2nd: x
3rd: x+1
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Equation:
2(x-1+x)= 3(x+1)+10
4x-2 = 3x+13
x = 15
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1st: x-1 = 14
2nd: 15
3rd 16
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Cheers,
Stan H.
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