Question 537259
y-y1 = m(x-x1)



y-5=(2/3)(x-1)



y-5=(2/3)x-(2/3)(1)



y-5=(2/3)x-2/3



y=(2/3)x-2/3+5



y=(2/3)x+13/3



So the answer is *[Tex \LARGE y = \frac{2}{3}x+\frac{13}{3}]



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