Question 536968
{{{(z-4)/(z-8)-(z+1)/(z+8)+(z-72)/(z^2-64)=(z-4)(z+8)/(z+8)(z-8)-(z+1)(z-8)/(z+8)(z-8)+(z-72)/(z+8)(z-8)=(z^2+4z-32)/(z+8)(z-8)-(z^2-7z-8)/(z+8)(z-8)+(z-72)/(z+8)(z-8)=(12z-96)/(z+8)(z-8)=12(z-8)/(z+8)(z-8)=12/(z+8)}}}