<PRE><B>Question 536873</B>
Three consecutive odd integers are n, n+2 and n+4&lt;P&gt;
For example 1, 3, and 5.  Note there is a difference of 2 between each consecutive odd integer.&lt;P&gt;
Sum1:  Their sum is n+n+2+n+4 = 3n+6 &lt;P&gt;
The largest integer is n+4 and 2 times the largest integer is 2*(n+4) = 2n+8.&lt;P&gt;
Sum2:  The sum of 2n+8 and 77 is 2n+8+77=2n+85.&lt;P&gt;
Now we have both sides.  Sum1=Sum2:&lt;P&gt;
3n + 6 = 2n + 85&lt;P&gt;
Subtract 2n from both sides, and subtract 6 from both sides.&lt;P&gt;
n=79.&lt;P&gt;
The consecutive integers are 79, 81, and 83.
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