Question 536799
To multiply (b+4)*(b+4) use FOIL - First times first, outside times outside, inside times inside, last times last.<P>
But before doing that write out exactly what is here.<P>
{{{((b+4)/2)^2 = ((b+4)(b+4))/(2*2)}}}<P>
{{{(3/(b+4))^3 = (3*3*3)/(b+4)(b+4)(b+4)}}}<P>
{{{(((b+4)(b+4))/(2*2))*((3*3*3)/(b+4)(b+4)(b+4))=((b+4)(b+4)*3*3*3)/(2*2*(b+4)(b+4)(b+4))}}}<P>
Notice that two of the (b+4)'s in the denominator cancel with the two (b+4)'s in the numerator.<P>
{{{27/4(b+4)}}}<P>
Check by setting b to something (try b=0).  Check it in the original equation and in the answer.  Don't use b=-4, because the expression is undefined when b=-4.<P>
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