Question 536805
<pre>
{{{4/(3x)}}} + {{{1/x}}} = {{{14/(3x^2)}}}

Clear of fractions by multiplying through by 3x²

{{{red(3x^2*"")}}}{{{4/(3x)}}} + {{{red(3x^2)*""}}}{{{1/x}}} = {{{red(3x^2)*""}}}{{{14/(3x^2)}}}


{{{red(cross(3)x^cross(2)*"")}}}{{{4/(cross(3)cross(x))}}} + {{{red(3x^cross(2))*""}}}{{{1/cross(x)}}} = {{{red(cross(3)cross(x^2))*""}}}{{{14/(cross(3)cross(x^2))}}}

4x + 3x = 14

     7x = 14

      x = 2

Edwin</pre>