Question 536715
they are travelling at right angles to each other.							
At any given instant they form a right triangle with their starting point							
Apply Pythagoras Theorem							
speed of one = x							
 other = x+5							
							
X^2 +	(x+	5	}^2	=	37	^2	
							
X^2  +	X^2+	10	x	*	25	=	1369
							
2	X^2	+	10	x-	-1344	=	0
Find the roots of the equation by quadratic formula							
							
a=	2	,b=	10	c	-1344		
							
b^2-4ac=	100	-	10752				
b^2-4ac=	10852						
{{{sqrt(	10852	)}}}=	104.17				
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-10	+	104.17	)/	4		
x1=	23.54						
x2=(	-10	-104.17	) /	4			
x2= 	-28.543						
Ignore negative value							
speed	=	23.54	mph

speed of cyclist A = 23.54 km/h

Add 5 to get speed of B				
m.ananth@hotmail.ca