Question 536709
find the area of a rectangle whose side is 5 feet and whose diagonal is {{{ sqrt(74)}}}
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Apply Pythagorean theorem to find the length of the other side:
Let x = length of other side of rectangle
then
{{{x^2 + 5^2 = (sqrt(74))^2}}}
{{{x^2 + 25 = 74}}}
{{{x^2 = 49}}}
{{{x = sqrt(49)}}}
{{{x = 7 }}} feet
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Area then is:
5*7 = 35 square feet