Question 536651
3+sqrt(z-7)=sqrt(z+8)

Square both sides.

(3+sqrt(z-7)^2 = (sqrt(z+8)^2


9 + z - 7 = z + 8

z + 2 = z + 8

At this point, we need to combine like terms.  However, when this is done, we can clearly see that z will cancel out.  

LOOK:

z - z = 8 - 2

0 = 6

This does not make sense since zero does not = 6.


What is the answer?


The answer, and this happens sometimes with radicals, is NO SOLUTION.


So, there is no solution to this radical equation.