Question 536640
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Equal logs with equal bases must have equal arguments.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(\varphi_1)\ =\ \log_b(\varphi_2)\ \Leftrightarrow\ \varphi_1\ =\ \varphi_2]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 1\ =\ x^2\ -\ x\ -\ 3]


Collect terms and solve the resulting quadratic equation.  Note: It won't factor over the rationals, so use the quadratic formula.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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