Question 536615
-6	x	+	8	y  	=	3				
Find the slope of this line 										
										
8	y  	=	6	x	+	3				
Divide by 	8									
	y  	=	3/4	x	+	0.38				
Compare this equation with y=mx+b										
slope m =	 3/4									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										-4/3
m1*m2=-1										
The slope of the required line will be 			-1 1/3							
										
m=	-4/3	,point	(	-3	,	-15	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-15	=	4.00	+	b						
b=	-19									
m=	-4/3									
The required equation is,y  	=-4/ 3	x		-19      			
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