Question 536545
-3b^4+b^3-(b^3+b^4-3)



-3b^4+b^3-b^3-b^4+3



(-3b^4-b^4)+(b^3-b^3)+3



-4b^4+3



So -3b^4+b^3-(b^3+b^4-3) = -4b^4+3