Question 536487
={{{(1/4)^2/(5/6-2/3)+7/12}}}
={{{(1/16)/((5-4)/6)+7/12}}}
={{{(1/16)/(1/6)+7/12}}}
={{{(1/16)(6/1)+7/12}}}
={{{(1/cross(16))(cross(6)/1)+7/12}}}
={{{(1/8)(3/1)+7/12}}}
={{{3/8+7/12}}}
={{{(9+14)/24}}}
={{{33/24}}}
={{{11/8}}}
={{{1&3/8}}}