<PRE><B>Question 536450</B>
Step 1 list the numbers and their squares.&lt;P&gt;
{{{1^2=2}}}&lt;BR&gt;
{{{2^2=4}}}&lt;BR&gt;
{{{3^2=9}}}&lt;BR&gt;
{{{4^2=16}}}&lt;BR&gt;
{{{5^2=25}}}&lt;P&gt;
Notice that the value in question isn&#39;t one of these perfect squares.  But it does lie between two of them.&lt;P&gt;
{{{9&lt;14&lt;16}}} Thus their square roots are in the same relationship.&lt;P&gt;
{{{sqrt(9)&lt;sqrt(14)&lt;sqrt(16)}}}&lt;P&gt;
Which means {{{3&lt;sqrt(14)&lt;4}}}&lt;P&gt;
Since 14 is closer to 16 than to 9, {{{sqrt(14)}}} will be closer to 4 than to 3.&lt;P&gt;
Plot it somewhere between 3 and 4, closer to 4 than to 3.
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