Question 536444
the point (5,y) is sqrt(17) units from (6,2). Find y.
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{{{d^2 = diffy^2 + diffx^2 = 17}}}
{{{(y-2)^2 + 1 = 17}}}
{{{(y-2)^2 = 16}}}
y - 2 = 4
y = 6
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y - 2 = -4
y = -2
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