Question 52826
The graph of your equation is: {{{graph(300,300,-5,5,-50,50,4x^3-28x^2+48x)}}}.  Note you can factor out 4x to get {{{4x(x^2-7x+12)}}}, which further factors to {{{4x(x-3)(x-4)}}}.  Taking those three factors shows us that the graph should cross the x-axis when x=0, x=3, and x=4.  All that means when x has those values, y is 0.