Question 536367
Let xy be the number x in ten's place and y in units place

4y=3x+5
4y-3x=5................(1)

10y+x= 10x+y+9
9y-9x=9
/9
y-x=1...................(2)

-3    	x	+	4	y	=	5	.............1	
-1	x	+	1	y	=	1	.............2	
Eliminate y								
multiply (1)by 		-1						
Multiply (2) by		4						
3	x		-4	y	=	-5		
-4	x	+	4	y	=	4		
Add the two equations								
-1	x				=	-1		
/	-1							
x	=	1						
plug value of 			x	in (1)				
-3    	x	+	4	y	=	5		
-3		+	4	y	=	5		
			4	y	=	5	+	3
			4	y	=	8		
				y	=	2
The number is 12

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