Question 536352
8 = 2^2 * 2
Sqrt8 = Sqrt(2^2*2)
The 2^2 can come out of the radical as 2...
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Therefore, Sqrt8 = 2*Sqrt2
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The solution to the problem Sqrt8 divided by Sqrt2 is 2*Sqrt2/Sqrt2
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The Sqrt2's cancel out and we are left w/ 2
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Happy Thanksgiving,
Lee