<PRE><B>Question 536317</B>
The distance from the x-axis to (2,3) is the radius, r = 5.
There are 2 points in the x-axis that are 5 units from the point (2,3).
The points are (x,0).
{{{d^2 = 25 = diffy^2 + diffx^2 = 3^2 + (2-x)^2}}}
{{{x^2 - 4x + 13 = 25}}}
{{{x^2 - 4x - 12 = 0}}}
(x - 6)*(x + 2) = 0
x = -2, x = 6
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{{{(x+2)^2 + y^2 = 5^2}}} Circle 1
{{{(x-6)^2 + y^2 = 5^2}}} Circle 2
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