Question 536215
Try this:
Let n = the term number and m the result, so...
n....m
1....2 = {{{2^1}}}
2....4 = {{{2^2}}}
3....8 = {{{2^3}}}
4....16 ={{{2^4}}}
5....32 ={{{2^5}}}
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.
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n....{{{2^n}}}
So the 100th term n = 100 and {{{2^100}}} = 1,267,650,600,228,229,401,496,703,205,376