<PRE><B>Question 536239</B>
Distance formula:  D = rt where r is the rate (speed) and t is time.&lt;P&gt;
In this case for part A:&lt;br&gt;
D = what must be found.&lt;br&gt;
r = 22 m/s&lt;br&gt;
t = 30 minutes * 60 seconds/minute = 1800 seconds.  (Convert minutes to seconds because the speed is given in meters per second.)&lt;P&gt;

D = 22*1800 = 39600 meters = 39.6 kilometers from town.&lt;P&gt;
Part B:  Use D=rt to find how far the train traveled in 50 seconds.&lt;br&gt;
D = what must be found.&lt;br&gt;
r = 22 m/s&lt;br&gt;
t = 50 seconds.&lt;P&gt;
D = 22 * 50 = 1100 meters.&lt;P&gt;
The train began 300 meters south of town, which the problem specifies as -300.  It moved 1100 meters north, which is +1100, so its position is now:&lt;P&gt;
1100-300= 800.  For the problem, +800 means 800 meters north of town.

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